Question

Factor each expression, if possible. Identify any special cases, such as the difference of squares or a perfect square trinomial xy-4y+2x-8

Answer 1

Answer:

$xy-4y+2x-8 = (y + 2)(x-4)$

Step-by-step explanation:

Given

$xy-4y+2x-8$

Required

Factor the expression

$xy-4y+2x-8$

Group the expression

$(xy-4y)+(2x-8)$

Factor each group

$y(x-4)+2(x-4)$

This gives:

$(y + 2)(x-4)$

Hence:

$xy-4y+2x-8 = (y + 2)(x-4)$