Respuesta :
According to the general rules and basic knowledge of physics, without any doubds I can say that a mole of red photons of wavelength 725 nm has [D] 165 kj of energy. I converted a wavelength into energy in that way :
[tex](E)= 6.023 x 10 ^23 x 6.625 x 10 ^ -34 x3 x 10^8/725x10^-9[/tex]=[tex]=0.1651 x10 ^ 6 J = 165 Kj.[/tex]
[tex](E)= 6.023 x 10 ^23 x 6.625 x 10 ^ -34 x3 x 10^8/725x10^-9[/tex]=[tex]=0.1651 x10 ^ 6 J = 165 Kj.[/tex]
Answer:
The energy of red photons of this particular wavelength is 2.7399×10^-22 kj
Explanation:
You can do this in two ways.
The first will be using the energy of a photon's expression:
E= hc/λ
where h is Planck's constant, c is the speed of light and λ is the photon's wavelength. Therefore,
E= (6.626×10⁻³⁴)(299792458)/(725×10⁻⁹)
E=2.7399×10⁻¹⁹ J
To get the answer to be in kilo-joules, we divide the answer above by 1000. Therefore, we get the final answer to be
E=(2.7399×10⁻¹⁹)/1000
E=2.7399×10⁻²² kj
The second way that you can calculate the energy of red photons is by using the expression
E=hf
where h is Planck's constant and f is the frequency of the photons.
When using this method, we first need to determine the frequency of the photons and this is done by using the expression
f=c/λ
where c is the speed of light constant and λ is the wavelength of the photons. Therefore,
f=299792458/725×10⁻⁹
f=4.135×10¹⁴ J/s
After determining the frequency, we can calculate the energy by using the expression
E=hf. Thus
E=(6.626×10⁻³⁴)(4.135×10¹⁴)
E=2.7399×10⁻¹⁹ J
To get the answer to be in kilo-joules, we divide the answer above by 1000. Therefore, we get the final answer to be
E=(2.7399×10⁻¹⁹)/1000
E=2.7399×10⁻²² kj