Question

9. If the perimeter of an isosceles triangle is 83 cm. and its base is 23 cm. Find the measure of its equal sides.


10. The perimeter of a rhombus is 5.6 cm. Find its side.


11. The perimeter of a rectangle is equal to that of a square with side 17 m. If the length of the
rectangle is 26 m. What is its breadth ?


12. What is the cost of fencing a rectangular field of length 16 m and breadth 11 m at the rate of 12 per m.

Please solve all questions..step by step.​

Answer 1

Required Answers :-

9.

Q:-If the perimeter of an isosceles triangle is 83 cm. and its base is 23 cm. Find the measure of its equal sides.

Answer:- As we know that Perimeter is the sum of all sides.

• Let the both side be x
• 83 = 23 + (x + x)
• 83 - 23 = 2x
• 60 = 2x
• 30 = x

Other two sides are 30 cm.

10.The perimeter of a rhombus is 5.6 cm. Find its side.

Answer:- As we know that

Side of Rhombus = Perimeter/4

• Side = 5.6/4
• Side = 1.4 cm
• Side is 1.4 cm

11.The perimeter of a rectangle is equal to that of a square with side 17 m. If the length of the

The perimeter of a rectangle is equal to that of a square with side 17 m. If the length of therectangle is 26 m. What is its breadth ?

Answer:- Perimeter of square = 4 × s

• Perimeter = 4 × 17
• Perimeter = 68 cm

Now,

• Perimeter of rectangle = 2(l + b)
• 68 = 2(26 + b)
• 68/2 = 26 + b
• 34 = 26 + b
• 34 - 26 = b
• 8 = b
• b=8

12.What is the cost of fencing a rectangular field of length 16 m and breadth 11 m at the rate of 12 per m.

Answer:- Perimeter = 2(l + b)

• Perimeter = 2(16 + 11)
• Perimeter = 2(27)
• Perimeter = 54 cm

Now,

• Total cost = 54 × 12
• Total cost = ₹648.

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