720 ways can the team choose one captain and then two assistants.
We need to find how many ways can the team choose one captain and then two assistants.
What is the formula to find the permutation?
The formula to find the permutation is [tex]nP_{r} =\frac{n!}{(n-r)!}[/tex].
Now, [tex]10P_{3} =\frac{10!}{(10-3)!}[/tex]
=10×9×8×7!/7!=720
Therefore, one captain and then two assistants can be chosen in 720 ways.
To learn more about the permutation visit:
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