Answer:
Step-by-step explanation:
BE is midsegment of ACDF
- BE = 1/2(CD + FA)
- 2(3x + 3) = 6x - 16 + 4x - 10
- 6x + 6 = 10x - 26
- 10x - 6x = 6 + 26
- 4x = 32
- x = 8
Similarly, FA is midsegment of BEZW
- FA = 1/2(BE + WZ)
- WZ = 2FA - BE
- WZ = 2(4x - 10) - (3x + 3)
- WZ = 8x - 20 - 3x - 3
- WZ = 5x - 23
Substitute x with 8:
- WZ = 5*8 - 23 = 40 - 23 = 17