Answer:
Please check the explanation.
Step-by-step explanation:
Given the statement:
''Twice the difference of a number and 2 is added to 6 and the result is 4 more than 3 times the number''.
Let us break down the statement into an algebraic expression.
First Portion:
Let the number be: n
The difference of a number n and 2: n -2
Twice the difference of a number n and 2: 2(n-2)
Twice the difference of a number and 2 is added to 6 = 2(n-2) + 6
Second Portion:
3 times the number n: 3n
4 more than 3 times the number: 3n + 4
Combine the First portion and Second Portion:
Twice the difference of a number and 2 is added to 6 and the result is 4 more than 3 times the number:
2(n - 2) + 6 = 3n + 4
Therefore, the required algebraic expression is:
BONUS SOLUTION to determine the number n
Let us solve the expression
2(n - 2) + 6 = 3n + 4
2n - 4 + 6 = 3n + 4
flip the equation
3n + 4 = 2n - 4 + 6
3n + 4 = 2n + 2
3n - 2n = 2 - 4
n = -2
Thus, the value of n = -2
