Question

In the Netherlands there is an annual ice-skating race called the "Tours of the eleven towns" the total distance of the course is 2.00*10 squared km and the record time is 5 hours, 40 minutes, and 37 seconds. Calculate the average speed for the record time.

Answer 1

1hr=60mins 5hr=5 × 60=300+40=340mins 1min=3600secs 340Mins=3600×340=1224000secs/10mins 2000÷10=200km/mins

Answer 2

Answer:

The average speed for the record time is 9.78 m/s.

Explanation:

Given that,

Total distance $d= 2.00\times10^2\ km$

Time $t= 5\times60\times60+40\times60+37\ sec$

$t =20437\ sec$

We need to calculate the average speed for the record time

Using formula of the average speed

$v_{avg}=\dfrac{D}{T}$

Where, D = total distance

T = total time

Put the value into the formula

$v_{avg}=\dfrac{2.00\times10^2\times10^{3}}{20437}$

$v_{avg}=9.78\ m/s$

Hence, The average speed for the record time is 9.78 m/s.