Question

A closed cylindrical tank of radius 3.5 m and height 2m is made from

a sheet of metal. How much sheet of metal is required ?​

Answer 1

Explanation:

Total surface area of cylinder:

$2\pi \times r(h + r) \\ 2 \times \pi \times 3.5(3.5 + 2) \\ 2\pi \times 19.25 = 120.951317 \\ 120.95 \: {cm}^{2}$

sheet of metal required = 120.95 cm^2

Answer 2

Explanation:

Answer:

Given :-

A closed cylindrical tank of radius 3.5 m and height 2 m is made from a sheet of metal.

To Find :-

How much sheet of metal is required.

Formula Used :-

${\red{\boxed{\large{\bold{T.S.A\: of\: cylinder\: =\: 2{\pi}r(r + h)}}}}}$

where,

r = Radius

h = Height

Solution :-

Given :

Radius = 3.5 m

Height = 2 m

According to the question by using the formula we get,

⇒ $\sf T.S.A =\: 2 \times \dfrac{22}{7} \times 3.5(3.5 + 2)$

⇒ $\sf T.S.A =\: 2 \times \dfrac{22}{7} \times 3.5(5.5)$

⇒ $\sf T.S.A =\: 2 \times \dfrac{22}{7} \times 3.5 \times 5.5T.S.A=2×722×3.5×5.5

⇒ \sf T.S.A =\: 2 \times \dfrac{22}{7} \times 19.25$

⇒ $\sf T.S.A =\: 2 \times 60.5$

➠ $\sf\bold{\purple{T.S.A =\: 121\: {m}^{2}}}$

∴ 121 m² of sheet of metal is required.