The coordinates of the vertices of a rectangle are (−3,2), (5,4), (6,0), and (−2,−2)
What is the perimeter of the rectangle, to the nearest tenth of a unit?
If we calculate the distance between two points, it is equivalent to one side of the rectangle. Using the distance formula: d = √((x₂ - x₁)² + (y₂-y₁)²) We compute the distance between the points (-3,2) and (5,4) d = √((5 + 3)² + (4 - 2)²) = √68 Now, we check the next two points: d = √((6 - 5)² + (0 - 4)² = √17 Now, we know that the adjacent sides of a rectangle are equal so the perimeter can be calculated using: P = 2(l₁ + l₂) P = 2(√68 + √17) =24.7 units.
