ccausey8477 ccausey8477

01-02-2021
Mathematics

contestada

I reallyyyy need help on this

I reallyyyy need help on this class=

Respuesta :

Аноним Аноним

01-02-2021

Answer:

4

Step-by-step explanation:

h(k(3))=[tex]\sqrt{2(3)+7+3}[/tex]

=4

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