A student solved the following problem and made an error:
Triangles ABC and DEF. Angles A and F are congruent and measure 63 degrees. Coordinates for the vertices are at A 1, 2 and B 1, 4 and C 3, 3 and D 5, 1 and E 3, 2 and F 5, 3.
Line 1 segment AB equals 2, segment FD equals 2, segment AB is congruent to segment FD
Line 2 ∠A ≅ ∠F
Line 3 Length of segment AC.
A (1, 2)
C (3, 3)
d equals square root of quantity x sub 2 minus x sub 1 squared plus quantity y sub 2 minus y sub 1 squared, then d equals square root of quantity 1 minus 3 all squared plus quantity 2 minus 3 all squared, then d equals square root of negative 2 squared plus negative 1 squared, then d equals square root of 4 plus 1, then d equals square root of 5
segment AC = 2.23
Line 4 Length of segment EF.
E (3, 2)
F (5, 3)
d equals square root of quantity x sub 2 minus x sub 1 squared plus quantity y sub 2 minus y sub squared then d equals square root of quantity 3 minus 5 all squared plus quantity 2 minus 3 all squared, then d equals square root of negative 2 squared plus negative 1, then d equals square root of 4 plus 1, then d equals square root of 5
segment EF= 2.23
Line 5 segment AC is congruent to segment FE
Line 6 triangle ABC is congruent to triangle EFDby SAS
In which line did the student make the first mistake?
Line 1
Line 5
Line 6
Line 2
