Following are the calculation to the given expression:
Given:
[tex]\to ^{12}{P_3}[/tex]
To find:
value=?
Solution:
Using formula:
[tex]\to \bold{^nP_r= \frac{n!}{(n-r)!}}[/tex]
[tex]\to \ {^{12}P_3= \frac{12!}{(12-3)!}}\\[/tex]
[tex]= \frac{12!}{9!}}\\\\= \frac{12 \times 11 \times 10 \times 9! }{9!}}\\\\= 12 \times 11 \times 10 \\\\=1320[/tex]
Therefore, the final answer is "1320".
Learn more about the permutation:
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