Answer:
we will use the sum of natural number series formula
if S=1+2+3+4+n, then
S= n(n+1) ;
2
Now, sum of all +ve integers from 0 to 200 is given by
S=0+1+2+3+200
=> S=200(200+1)/2;
=>S=20100;
Sum of all +ve integers divisible by 5 is given by
R=0+5+10+15+20+25+30+200
R=5(1+2+3+4+5+6+40)
R=5*40(40+1)/2
R=4100 ;
therefore the sum of all +ve integers <200 and not divisible by 5=S-R=16000
Step-by-step explanation:
