Answer:
x = [tex]\frac{8y-4}{3y+2}[/tex]
Step-by-step explanation:
Given
3xy + 4 = 8y - 2x ( add 2x to both sides )
3xy + 2x + 4 = 8y ( subtract 4 from both sides )
3xy + 2x = 8y - 4 ← factor out x from each term on the left side
x(3y + 2) = 8y - 4 ← divide both sides by (3y + 2)
x = [tex]\frac{8y-4}{3y+2}[/tex]
