Energy required : 2508 J
Further explanation
Given
V= 120 ml
Δt = 5°C
Required
Heat needed
Solution
Heat can be formulated :
Q = m.c.Δt
m = mass, g
c = specific heat, joules / g °C (water=4.18 J.g °C)
∆T = temperature difference, ° C / K
mass water = 120 g(density = 1 g/ml)
Input the value :
Q = 120 g x 4.18 J.g °C x 5 °C
Q = 2508 J
