Question

At what temperature will 7.2 moles of a gas under 107.5 kPa of pressure that takes up 748 cm^3 be?

Answer 1

The temperature = T = 1.29 K

Further explanation

Given

n = 7.5 moles

P = 107.5 kPa = 1,0609425 atm

V = 748 cm³ = 0.748 L

Required

Temperature

Solution

Ideal gas law :

PV = nRT

T = (PV)/(nR)

T = (1,0609425 x 0.748)/(7.5 x 0.08205)

T = 1.29 K