If a horse trots past the fence post located 14 m to the left of the gate post and then passed another fence post located 15 m to the right of the gate Post 14 seconds later what is the average velocity of the horse

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Answer:

19 miles away from the home

The average velocity of the horse at the given displacement is 2.07 m/s.

The given parameters:

  • Initial position of the horse, x₁ = 14 m left
  • Final position of the horse, x₂ = 15 m right
  • Time of motion of the horse, t = 14 s

The average velocity of the horse is determined as the ratio of the total displacement to time of motion.

[tex]v = \frac{\Delta x}{\Delta t} \\\\v = \frac{x_2 - x_1 }{t} \\\\v = \frac{15 - (-14)}{14} \\\\v = \frac{15 + 14}{14} \\\\v = \frac{29}{14} \\\\v = 2.07 \ m/s[/tex]

Thus, the average velocity of the horse at the given displacement is 2.07 m/s.

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