Answer: 90 m/s
Explanation:
Given
mass of racecar [tex]M=1.2\times10^3\ kg[/tex]
velocity of racecar [tex]u=8\ m/s[/tex]
mass of still honeybadger [tex]m=80\ kg[/tex]
after collision race car is traveling at a speed of [tex]v_1=2\ m/s[/tex]
conserving linear momentum
[tex]Mu+m\times0=Mv_1+ mv_2\quad[v_2=\text{velocity of honeybadger after colllision}][/tex]
[tex]1.2\times10^3\times8+0=1.2\times10^3\times2+80\times v_2[/tex]
[tex]1.2\times10^3(8-2)=80v_2\\v_2=\frac{7.2\times10^3}{80}=90\ m/s[/tex]