Respuesta :
we know that
The center-radius form of the circle equation is in the format
[tex] (x-h)^{2} +(y-k)^{2} =r^{2} [/tex]
where
(h,k) is the center of the circle
r is the radius of the circle
In this problem
we have
[tex] (x -5)^{2} + (y + 6)^{2} = 4^{2} [/tex]
where
the center (h,k) is the point [tex] (5,-6) [/tex] and the radius is equal to [tex] 4 [/tex] units
therefore
the answer is
The center of the circle is the point [tex] (5,-6) [/tex]
