Respuesta :

center = (5, -6)
.....................

we know that

The center-radius form of the circle equation is in the format

[tex] (x-h)^{2} +(y-k)^{2} =r^{2} [/tex]

where

(h,k) is the center of the circle

r is the radius of the circle

In this problem

we have

[tex] (x -5)^{2} + (y + 6)^{2} = 4^{2} [/tex]

where

the center (h,k) is the point [tex] (5,-6) [/tex] and the radius is equal to [tex] 4 [/tex] units

therefore

the answer is

The center of the circle is the point [tex] (5,-6) [/tex]

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