Question

currently Samsung ships 21.9% of the organic light-emitting diode (OLED) displays in the world. Let S be the event that a randomly selected OLED display made by samsung.

Find P(S).
(Round your answer to 3 decimal places.)

Find P(S’)
(Round your answer to 3 decimal places.)

Find odds in the favor of event S.
(Round your answer to 3 decimal places.)

Find odds against event S.
(Round your answer to 2 decimal places.)

Answer 1

Answer:

Step-by-step explanation:

Find P(S): P(A) + P(A')= 1

A and A' together comprise the sample space, their probabilities sum 1

(Turn 21.9% into a decimal) P(S)= 0.219

Find P(S'): P(A')= 1-P(A)

The probability of the compliment of A is found by subtracting P(A) from 1.

1 -0.219= 0.781; P(S')= 0.781

Find odds in the favor of events S.

(Round 3 decimal places.)

P(A) / 1- P(A)

.219 /.781= .280

Find odds against event S.

(Round your answer to 2 decimal places)

1- P(A) / P(A)

0.781 / .219= 3.566 ROUNDED 3.57

Answer 2

Using probability concepts, it is found that:

• P(S) = 0.219.

• P(S') = 0.781.

• The odds in favor of event S are 0.281.

• The odds against event S are 3.57.

21.9% of the organic light-emitting diode (OLED) displays in the world are made by Samsung, hence:

• P(S) is the probability of a chip being made by Samsung, hence P(S) = 0.219.
• P(S') is the probability of a chip not being made by Samsung, hence P(S') = 1 - 0.219 = 0.781.

The odds in favor of an event with probability p is given by:

$\frac{p}{1 - p}$

Hence, the odds in favor of event S are:

$\frac{0.219}{0.781} = 0.28$

The odds against event S are:

$\frac{0.781}{0.219} = 3.57$

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