Question

What are the x- and y-intercepts of −6x+4y=96 ?

Answer 1

* intercepts "x" --> y=0

-6x  + 4(0) = 96
-6x = 96
x = $- \frac{96}{6}$

x = 16  

(16,0)

*intercepts "y" --> x=0

-6(0) + 4y = 96
4y = 96
y = $\frac{96}{4}$

y = 24

(0,24)