Answer:
h = 17.65 m
Step-by-step explanation:
The given equation gives the speed at impact :
[tex]v=\sqrt{2gh}[/tex]
h is height form where the object is dropped
Put v = 18.6 m/s in the above equation.
[tex]h=\dfrac{v^2}{2g}\\\\h=\dfrac{(18.6)^2}{2\times 9.8}\\\\h=17.65\ m[/tex]
So, the object must be dropped from a height of 17.65 m.