Answer:
v = 35.11 m / s, θ = 20º north of east
Explanation:
This is a compound problem of relative velocities, we can use the Pythagorean theorem to find the modulus of the resulting velocity
v² = v₁² + v₂²
where the eastward velocity is v₁=33 m/s and the northward velocity
v₂=12 m / s
v = [tex]\sqrt{33^2 +12^2}[/tex]
v = 35.11 m / s
the direction of this velocity can be found with the uses of trigonometry
tan θ = v₂ / v₁
θ = tan⁻¹ v₂ / v₁
θ = tan⁻¹ 12/33
θ = 20º
this angles is north of east
