Question

denzel wants to work out the density,in g/cm cubed, of a block of wood,The block of wood is in the shape of a cuboid.His measurements are
length 17.7cm
width of 8.3cm and
height 13.0cm .]

He also measured the mass at 2090g.By considering bounds,work out the density of the wood.Give your answer to a suitable degree of accuracy Show all your working and give full reason for your answer

Answer 1

Answer:

Density of cuboid box = 1.09 g/cm cubed

Step-by-step explanation:

Given that:

Length of cuboid box = 17.7 cm

Width of box = 8.3 cm

Height of box = 13.0 cm

Mass of box = 2090 grams

Density = Mass/Volume

We will find the volume first.

Volume of box = Length * Width * Height

Volume of box = 17.7 * 8.3 * 13.0 = 1909.8 cm cubed

Density = $\frac{2090}{1909.8}$

Density = 1.09 g/cm cubed

Hence,

Density of cuboid box = 1.09 g/cm cubed

Answer 2

Answer:

it must be correct as it is legit it.

0.011g/cm^3

Step-by-step explanation:

first you must consider that the overall LB=LB/UB

and the overall UB=UB/LB

now convert all values except for mass into MM by multiplying by 10:

177mm

83mm

130mm

now consider the bounds specified, to the nearest mm

1/2=0.5 as that is the midpoint for both bounds

so LB and UB are as follows

LB---> 176.5,82.5,129.5 respectively

UB---> 177.5,83.5,130.5 respectively

UB and LB for mass is 2090g+- 2.5g so

UB=2092.5

LB=2087.5

LB volume= 188568.1875cm³

UB volume=193417.3125cm³

so the overall UB for the density is= UB(mass)/LB(volume)=0.01109678164g/cm^3

overall LB=LB/UB=0.0107927257g/cm^3

Now an error interval is needed as a suitable degree of accuracy is required

0.0107927257g/cm^3<Density≤0.01109678164g/cm^3

now consider that both of these bounds have a common rounded number which is 0.011g/cm^3 to 2 s.f. so that is the answer, asdly i cannot write it in the way mathswatch wants it but i am adamant its correct.