[tex] \frac{1}{2} y - 9 > 1[/tex]
[tex] \frac{y}{2} - 9 > 1[/tex]
[tex] \frac{y}{2} > 1 + 9 \\ \frac{y}{2} > 10 \\ y > 10 \times 2 \\ y > 20[/tex]
We have to compare and consider both values which are y = 20 and any greater than 10 which is 21.
Substitute y = 20 in the Inequality.
[tex] \frac{20}{2} - 9 > 1 \\ 10 - 9 > 1 \\ 1 > 1 \longrightarrow \sf{false}[/tex]
Substitute y = 21 in the Inequality.
[tex] \frac{21}{2} - 9 > 1 \\ 21 - 18 > 2 \\ 3 > 2 \longrightarrow \sf{true}[/tex]
That means the value of y must be greater than 20. Hence the answer is B choice.
[tex] \large \boxed{y > 20}[/tex]