ayenoe13
ayenoe13 ayenoe13
  • 30-01-2021
  • Mathematics
contestada

Can you guys help we with this question. ​​​​​​

Can you guys help we with this question class=

Respuesta :

khatiwadamaheep khatiwadamaheep
  • 30-01-2021

Answer:

40

Step-by-step explanation:

(2x+1/(2x))^5 *(2x -1/(2x))^5

= ((2x)^2 -1/(2x)^2)^5 (a+b)*(a-b) =a2-b2

= (4x^2-1/4(x)^2)^5

now

x =4x^2. ,a = 1/4(x)^2 ,n =5

we have

general term = Cr *x^r *a^(n-r)

= Cr * (4x^2)^r * (1/4(x)^2)^(n-r)

= Cr *4^r * X^2r * 1/( 4^(n-r) *x^(2n-2r)

= Cr * 4^r/4^(n-r) * x^(2r)/x^(2n-2r)

= Cr * 4(2r-n) *x(4r-2n)

now for x^2

4r-2n = 2

4r -10=2

4r =12

r = 3

now for coeff

C(5,3) * 4^(2*3-5)

5!/(3!*(5-3)!) * 4

5*4/(2*1)*4

40

Answer Link
Renidelancey
Renidelancey Renidelancey
  • 30-01-2021
4r-2n=2

4r-10=2

4r=12

R=13
Answer Link

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