Answer:
Effi = 75 %
Explanation:
That is, the 6000 [J] is electrical energy that is transferred to the liquid, of that amount of energy 1500 [J] is dissipated or lost.
That is, from that amount of energy the difference between the energy that is supplied and the one that is lost is the energy that absorbs the liquid in the kettle.
[tex]Q=6000-1500\\Q=4500[J][/tex]
That is 4500 [J] enter the liquid that is heated.
Efficiency can be calculated as the amount of energy that the liquid receives over the energy that is supplied.
[tex]Effi = 4500/6000\\Effi = 0.75[/tex]
