Answer:
Approximate maximum height is 5 ft
[tex]h(\frac{18}{32} )= 5 \ ft[/tex]
Step-by-step explanation:
[tex]h(t)=-16t^{2} + 18t[/tex] ---------- (1)
Differentiate equation (1) w.r.t t and equate it to zero (in order to determine maxima)
[tex]h^{'}(t) = -32t+18[/tex]
[tex]0= -32t+18[/tex]
[tex]t=\frac{18}{32}[/tex]
Substitute this value in equation (1)
[tex]h(\frac{18}{32} )=-16(\frac{18}{32} )^{2} + 18(\frac{18}{32} )[/tex]
[tex]h(\frac{18}{32} )=-5+ 10[/tex]
[tex]h(\frac{18}{32} )= 5 \ ft[/tex]
