PLEASE HELP I DON'T KNOW HOW TO SOLVE THIS.

Answer: b
Step-by-step explanation:
X is defined for all numbers on the domain starting at x=0. It doesn’t show or mention a cutoff/equation in the picture so it’s safe to assume it continues forever
To find the domain from the graph, you have to focus only x-axis because domain is the set of x-value.
From the graph, we can see that domain starts at x = 0 and keeps going and going positive infinitely. That means the domain must be greater or equal to 0.
Here is an easier way to understand
[tex]\large \boxed{ \sf{left/start}} \Longrightarrow \large \boxed{ \sf{right/end}}[/tex]
[tex] \large \sf{left = 0} \\ \large \sf{right = + \infin}[/tex]
And if we combine both, we get
[tex]0 \leqslant x \leqslant + \infin[/tex]
But we don't usually write positive infinity, therefore we convert to
[tex]0 \leqslant x \longrightarrow x \geqslant 0 \\ x \geqslant 0[/tex]
[tex]x \geqslant 0[/tex]
If you have any questions related to this answer, feel free to ask in comment.
To find the domain from the graph, you have to focus only x-axis because domain is the set of x-value.
From the graph, we can see that domain starts at x = 0 and keeps going and going positive infinitely. That means the domain must be greater or equal to 0.
Here is an easier way to understand
[tex]\large \boxed{ \sf{left/start}} \Longrightarrow \large \boxed{ \sf{right/end}}[/tex]
[tex] \large \sf{left = 0} \\ \large \sf{right = + \infin}[/tex]
And if we combine both, we get
[tex]0 \leqslant x \leqslant + \infin[/tex]
But we don't usually write positive infinity, therefore we convert to
[tex]0 \leqslant x \longrightarrow x \geqslant 0 \\ x \geqslant 0[/tex]
[tex]x \geqslant 0[/tex]
If you have any questions related to this answer, feel free to ask in comment.