The nuclear equation :
₈₂²¹⁴Pb ⇒ ₈₃²¹⁴Bi + ₋₁⁰e
Given
₈₂²¹⁴Pb
beta β ₋₁e⁰ particles
Required
Nuclear equation
Solution
Radioactivity is the process of unstable isotopes to stable isotopes by decay, by emitting certain particles,
The principle used is the sum of the atomic number and mass number before and after the decay reaction is the same
The reaction
₈₂²¹⁴Pb ⇒ X + ₋₁⁰e
The element X has
-the atomic number = 82 + 1 = 83
-the mass number = 214
In the periodic system, the element with atomic number 83=Bismuth