Question

A golfer strikes a 0.059-kg golf ball with a force of 290 N. If the ball moves with a velocity of 69 m/s,
calculate the time the ball is in contact with the club.

Answer 1

Answer:

0.014s

Explanation:

Given parameters:

mass of golf ball  = 0.059kg

force applied  = 290N

velocity = 69m/s

initial velocity  = 0m/s

Unknown:

Time of contact  = ?

Solution;

We know that momentum is the quantity of motion of body possess;

  Momentum  = mass x velocity

  Momentum  = 0.059 x 69  = 4.1kgm/s

Also; impulse is the effect of the force acting on a body;

  impulse  = force x time  = momentum

  So;

            Force x time  = momentum

                  Time  = $\frac{momentum}{force }$    = $\frac{4.1}{290}$    = 0.014s