Step-by-step explanation:
[tex] \underline{ \underline{ \text{Given : }}}[/tex]
- Perpendicular ( P ) = VT = 2
- Base ( b ) = PT
- [tex] \theta = \tt{60 \degree}[/tex]
[tex] \underline{ \underline{ \text{Solution}}} : [/tex]
[tex] \tt{ \tan(60 \degree) = \frac{perpendicualar}{base}} [/tex]
⟶ [tex] \tt{ \sqrt{3} = \frac{2}{PT}} [/tex]
⟶ [tex] \tt{ \sqrt{3} \: PT= 2}[/tex]
⟶ [tex] \tt{PT = \frac{2}{ \sqrt{3}} } [/tex]
⟶ [tex] \tt{PT= \boxed{\tt{ \frac{2 \sqrt{3} }{{3} }}}} [/tex]
Hope I helped ! ♡
Have a wonderful day / night ! ツ
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