Question

two resistors of resistance 6 ohm and 3 ohm are connected in series and then in parallel .calculate the equivalent series resistance and equivalent parallel resistance.​

Answer 1

Explanation:

Given that,

Two resistors of resistance 6 ohm and 3 ohm are connected in series and then in parallel.

For series combination,

$R_{eq}=R_1+R_2$

For parallel combination,

$\dfrac{1}{R_{eq}}=\dfrac{1}{R_1}+\dfrac{1}{R_2}$

When 6 ohm and 3 ohm are in series,

$R_s=6+3\\\\R_s=9\ \Omega$

When 6 ohm and 3 ohm are in paralle,

$\dfrac{1}{R_p}=\dfrac{1}{6}+\dfrac{1}{3}\\\\R_p=2\ \Omega$

So, the equivalent resistance in series combination is 9 ohms and in parallel combination it is 2 ohms.

Answer 2

Explaination :

As we know that, if n resistances R1 , R2 and R3 .... Rn are joined in parallel the equivalent resistance is given as :

• 1/Rp = 1/R1 + 1/R2 + 1/R3 ... 1/Rn

Here,

• R is resistance

We have :

• R1 = 6Ω
• R2 = 3Ω

Substituing the values :

• Refer the attachment.