Answer:
[tex]\displaystyle d = \sqrt{17}[/tex]
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Algebra I
- Reading a Cartesian Plane
- Coordinates (x, y)
Algebra II
- Distance Formula: [tex]\displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
Step-by-step explanation:
Step 1: Define
Point (-3, 2)
Point (-4, 6)
Step 2: Find distance d
Simply plug in the 2 coordinates into the distance formula to find distance d
- Substitute in points [Distance Formula]: [tex]\displaystyle d = \sqrt{(-4--3)^2+(6-2)^2}[/tex]
- [√Radical] (Parenthesis 1) Simplify: [tex]\displaystyle d = \sqrt{(-4+3)^2+(6-2)^2}[/tex]
- [√Radical] (Parenthesis) Add/Subtract: [tex]\displaystyle d = \sqrt{(-1)^2+(4)^2}[/tex]
- [√Radical] Evaluate exponents: [tex]\displaystyle d = \sqrt{1+16}[/tex]
- [√Radical] Add: [tex]\displaystyle d = \sqrt{17}[/tex]