Question

Please Help ASAP
Find the value of x, y, and z. Round to the nearest tenth if needed.

Answer 1

Answer:

z^2 = y^2 + 6^2........equation 1

x^2 = y^2 + 24^2.....equation 2

30^2 = z^2 + x^2.......equation 3

put equation 1 and 2 in 3

30^2 = (y^2 +6^2) + (y^2 + 24^2)

900 = y^2 + 36 + y^2 + 576

900 = 2y^2 + 612

2y^2 = 900 - 612 = 288

divide both side by 2

y^2 = 144

find the square root of both sides

y = 12

recall

z^2 = y^2 + 6^2

z^2 = 144 + 36

z^2 = 180

z = 13.42

recall

x^2 = y^2 + 24^2

x^2 = 144 + 576

x^2 = 720

x = 26.83

Step-by-step explanation:

you get your 3 equations from the diagram above which as 3 triangles in it using pythagoras theorem