Question

A 25,000 kg jet is sitting still on the runway (O
m/s). If the jet goes to take off and reaches 80
m/s in 10 seconds, how much force was required
to get it there?

Answer 1

Answer:

The force required to get it there is 200000 N.

Explanation:

The force can be calculated by the second Newton's law:

$F = ma$

Where:

m: is the mass = 25000 kg

a: is the acceleration

The acceleration is given by:

$a = \frac{v}{t}$

Where:

v: is the velocity = 80 m/s

t: is the time = 10 s

$a = \frac{v}{t} = \frac{80 m/s}{10 s} = 8 m/s^{2}$

Hence, the force is:

$F = ma = 25000 kg*8 m/s^{2} = 200000 N$

Therefore, the force required to get it there is 200000 N.

I hope it helps you!