Question

A rocket is fired upward from the ground with an initial velocity of 200 feet per second. Neglecting air​ resistance, the height of the rocket at any time, t, can be described in feet by the equation H=−16t2+200t. Find the height of the rocket at t=3 seconds.

Answer 1

Answer:

744 ft

Step-by-step explanation:

All you have to do is plug in 3 wherever there is a t and then do the math in which you will get 744

Answer 2

Answer:

The height of the rocket is 456 feet

Step-by-step explanation:

Substitute the given value for the variable, and then simplify.

Took the quick check :)