Question

A tennis ball is shot straight up with an initial velocity of 34 m/s. What is its velocity two seconds after launch?

Answer 1

Answer:

The speed after 2 seconds is 14.4 m/s

Explanation:

Vertical Launch Upwards

In a vertical launch upwards, an object is launched vertically up from a height H without taking into consideration any kind of friction with the air.

The speed changes from an initial value vo to a final value vf, given by:

$v_f=v_o-g.t$

Where g is the gravitational acceleration ($9.8\ m/s^2$)

The tennis ball is shot up with an initial speed of vo=34 m/s. We are required to find the final speed at t=2 s:

$v_f=34-9.8*2$

$v_f=14.4\ m/s$

The speed after 2 seconds is 14.4 m/s

Answer 2

the velocity after 2 seconds of launch is 14.4 m/s

the initial velocity(a) is 34m/s

the time(t) is 2 seconds

acceleration(a) due to gravity is 9.8g

the formula is

v= u - at

v= 34 -(9.8)(2)

= 34 - 19.6

= 14.4 m/s

hence the final velocity is 14.4 m/s

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