If 3.75 moles of aluminum react, how many moles of sulfur are needed?

16 Al + 3S8 --> 8Al2S3
0.70 mol




0.050 mol


20 mol




16 mol

Respuesta :

Answer:(A) 0.70 mol

Explanation:

Oseni

The moles of sulfur needed would be 0.7.

From the equation of the reaction, the mole ratio of Al to S8 is 16:3, meaning that for every 16 moles of Al, 3 moles of S8 would be required.

Thus, if 3.75 moles of Al react, the mole of S8 that would be required can be calculated as:

  •   16 moles of Al = 3 moles of S8
  •    3.75 moles of Al = ?

                                    = 3 x 3.75/16

                                     = 0.7 moles

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