Question

How many moles at of a gas will occupy 2.5 L at STP?



We need to answer the question with steps of that method.

Answer 1

Explanation:

Volume of gas = 2.50 L

Temperature = 273 K

Pressure = 1 atm

Moles of gas = ?

Solution:

PV = nRT

n = PV/RT

n = 1 atm× 2.50 L / 0.0821 atm. L. K⁻¹.mol⁻¹ . 273 K

n = 2.5 atm. L /22.4 atm. L. mol⁻¹

n = 0.112 mol