Well, if I can remember correctly-
1.) (c^2 +4c) I believe you would rewrite in factored form to get a solution of c(c + 4)
2.) (4w^2 -4) I think you would the 4w^2 first, getting 16w. Then the solution would be 16w - 4 (since you cannot combine these terms together)
3.) (z^2 - 2z) You would do the same with this as you would with question 1, which would give you a solution of z(z + 2)
