Answer:
[tex]N(t) = \frac{1000}{1 + 0.9e^{-0.2t}}[/tex]
Step-by-step explanation:
The logistic function has the following format:
[tex]N(t) = \frac{K}{1 + (\frac{K - P_0}{P_0})e^{-rt}}[/tex]
In which:
K is the carrying capacity(maximum population).
[tex]P_0[/tex] is the initial number.
r is the growth rate, as a decimal.
There are currently 100 cases of flu in a small town of population 1,000 people
This means that [tex]P_0 = 100, K = 1000[/tex]
Early in the flu epidemic, the number of cases is increasing by 20% each day.
This means that [tex]r = 0.2[/tex]
Function:
[tex]N(t) = \frac{K}{1 + (\frac{K - P_0}{P_0})e^{-rt}}[/tex]
[tex]N(t) = \frac{1000}{1 + (\frac{1000 - 100}{1000})e^{-0.2t}}[/tex]
[tex]N(t) = \frac{1000}{1 + 0.9e^{-0.2t}}[/tex]