Question

Find the missing variables

Answer 1

Answer:

Solution,

tan45 = $\frac{u}{v}$

or, 1 =  $\frac{u}{v}$

or, v = u

Now,

Using Pythagoras Theorem,

$(8\sqrt{2})^{2} = u^{2} +v^{2}\\or, 128 = u^{2} +u^{2}\\or, 128 = 2u^{2}\\or, u^{2} = 64\\\\or, u = 8cm = v$

Answer 2

Step-by-step explanation:

$\underline{ \underline{ \text{Given}}} :$

• Hypotenuse ( h ) = 8√2
• Perpendicular ( p ) = u
• Base ( b ) = v
• $\tt{ \theta = 45 \degree}$

$\underline{ \underline {\text{To \: find}}} :$

• Value of u & v

$\underline{ \underline{ \text{Solution}}}\:$ :

$\tt{sin \: \theta = \frac{p}{h}}$

⟶ $\tt{ \sin(45 \degree) = \frac{u}{8 \sqrt{2} } }$

⟶ $\tt{ \frac{1}{ \sqrt{2} } = \frac{u}{8 \sqrt{2}} }$

⟶ $\tt{ \sqrt{2 \: } u = 8 \sqrt{2}}$

⟶ $\tt{u = \frac{8 \sqrt{2} }{ \sqrt{2}} }$

⟶ $\tt{u = 8}$

Again ,

$\tt{tan \: \theta = \frac{p}{b}}$

⟶ $\tt{ \tan(45 \degree) = \frac{8}{v}}$

⟶ $\tt{1 = \frac{8}{v}}$

⟶ $\tt{v = 8}$

$\red{ \underline{ \boxed{ \boxed{ \text{Our \: final \: answer : \boxed{ \tt{u = 8 \: and \: v = 8}}}}}}}$

Hope I helped ! ♡

Have a wonderful day / night ! ツ

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁