Question

f(n) = 4n +3
g(n) = 3n²+2
Find f(n) - g(n)
help lol

Answer 1

Answer:

$(4n + 3) - (3 {n}^{2} + 2) \\ = 4n + 3 - 3 {n}^{2} - 2 \\ = - 3 {n }^{2} + 4n + 1 \\ ( - 3 {n}^{2} - 3n) - (1n + 1) \\ - 3n(n + 1) - 1(n + 1) \\ (n + 1)( - 3n - 1) \\ n = - 1 \\ n= \frac{1}{ - 3}$

Answer 2

Answer:

$f(n) - g(n) = (4n + 3) - (3 {n}^{2} + 2) \\ = 4n + 3 - 3 {n}^{2} - 2 \\ = \boxed{4n - 3 {n}^{2} + 1}$

(4n²-3n+1) is the right answer.