Question

50POINTS!
Using the ideal gas law (PV=nRT) solve for the missing. Variable. R= 0.08206atm*L/mol*k

If 22.9L of an ideal gas was collected at STP. How many moles of the gas were present?

A. 1.02 moles
B. 5.99 moles
C. 3.05 moles
D. 2.74 moles

Answer 1

Answer:

A. 1.02 moles .

Explanation:

Hello!

In this case, given the ideal gas equation, as we need to solve for moles, we divide both sides by RT to get:

$n=\frac{PV}{RT}$

Thus, by plugging in the pressure and temperature at STP (1.00 atm and 273.15 K respectively) we obtain:

$n=\frac{1.00atm*22.9L}{0.08206\frac{atm*L}{mol*K}*273.15K}\\\\n=1.02mol$

Therefore, the correct answer is A. 1.02 moles

Best regards!