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Determine the number of representative particles in each substance.
a. 4.45 mol of C6H1206
b. 0.250 mol of KNO3
c. 2.24 mol of H2
d. 9.56 mol of Zn

Respuesta :

Answer:

a) 26.79 * 10^23 particles

b) 1.51  * 10^23 particles

c) 13.5 * 10^23 particles

d) 57.6 * 10^23 particles

Explanation:

a) 1 mole of a substance contains 6.02 * 10^23 particles

4.45 mol of C6H1206 contains 4.45 * 6.02 * 10^23 particles = 26.79 * 10^23 particles

b) 1 mole of a substance contains 6.02 * 10^23 particles

0.250 mol of KNO3 contains 0.250 * 6.02 * 10^23 particles = 1.51  * 10^23 particles

c)  1 mole of a substance contains 6.02 * 10^23 particles

2.24 mol of H2 contains 2.24 * 6.02 * 10^23 particles = 13.5 * 10^23 particles

d) 1 mole of a substance contains 6.02 * 10^23 particles

9.56 mol of Zn contains  9.56 * 6.02 * 10^23 particles= 57.6 * 10^23 particles

A. The number of particles in 4.45 moles of C₆H₁₂O₆ is 2.68×10²⁴ particles.

B. The number of particles in 0.250 mole of KNO₃ is 1.51×10²³ particles.  

C. The number of particles in 2.24 moles of H₂ is 1.35×10²⁴ particles.

D. The number of particles in 9.56 moles of Zn is 5.76×10²⁴ particles.

From Avogadro's hypothesis, we understood that:

1 mole of any substance = 6.02×10²³ particles

With the above information in mind, we can obtain the answers to the questions as follow:

A. Determination of the number of particles in 4.45 moles of C₆H₁₂O₆.

1 mole of C₆H₁₂O₆ = 6.02×10²³ particles

Therefore,

4.45 moles of C₆H₁₂O₆ = 4.45 × 6.02×10²³

4.45 moles of C₆H₁₂O₆ = 2.68×10²⁴ particles

B. Determination of the number of particles in 0.250 mole of KNO₃

1 mole of KNO₃ = 6.02×10²³ particles

Therefore,

0.250 mole of KNO₃ = 0.250 × 6.02×10²³

0.250 mole of KNO₃ = 1.51×10²³ particles

C. Determination of the number of particles in 2.24 moles of H₂

1 mole of H₂ = 6.02×10²³ particles

Therefore,

2.24 moles of H₂ = 2.24 × 6.02×10²³

2.24 moles of H₂ = 1.35×10²⁴ particles

D. Determination of the number of particles in 9.56 moles of Zn

1 mole of Zn = 6.02×10²³ particles

Therefore,

9.56 moles of Zn = 9.56 × 6.02×10²³

9.56 moles of Zn = 5.76×10²⁴ particles

Learn more about Avogadro's number:

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