Answer:
a) F =489.95 N
b) W = 490 N
c) both have same value
Explanation:
a)
The force of gravitation between two objects is given by Newton's Law of Gravitation. According to this law:
[tex]F = \frac{Gm_{1}m_{2}}{r^{2}}\\[/tex]
where,
F = Gravitational Force between the person and Earth = ?
G = Universal Gravitational Constant = 6.67 x 10⁻¹¹ Nm²/kg²
m₁ = mass of peerson = 50 kg
m₂ = mass of earth = 5.98 x 10²⁴ kg
r = distance between person and earth = radius of earth = 6.38 x 10⁶ m
Therefore,
[tex]F = \frac{(6.67\ x\ 10^{-11}\ Nm^{2}/kg^{2})(50\ kg)(5.98\ x\ 10^{24}\ kg)}{(6.38\ x\ 10^{6}\ m)^{2}}\\\\[/tex]
F = 489.95 N
b)
The weight of the person will be given as:
[tex]W = m_{1}g\\W = (50\ kg)(9.8\ m/s^{2})[/tex]
W = 490 N
c)
Both have same value
