Question

A bucket tied to a rope is moving at a constant speed of 5.0 m/s in a circle of radius
2.0 m. Calculate the approximate magnitude of the centripetal acceleration of the bucket.
The below answer choices are in m/s^2

A.) 2.5
B.) 6.2
C.) 12.5
D. None of these

Answer 1

Answer:

$a=12.5\ m/s^2$

Explanation:

Given that,

The speed of the bucket tied to a rope, v = 5 m/s

The radius of the circle, r =2 m

We need to find the magnitude of the centripetal acceleration of the bucket. The formula for the centripetal acceleration is given by :

$a=\dfrac{v^2}{r}\\\\a=\dfrac{(5)^2}{2}\\\\a=12.5\ m/s^2$

So, the centripetal acceleration of the bucket is $12.5\ m/s^2$.