Answer:
the department should offer 50 sections of finite math and 60 section of applied calculus in order to fill all sections and accommodate all of the students
Step-by-step explanation:
Given the data in the question'
let x represent number of sections of finite math while y represent number of section of applied calculus.
as 6000 student will like to take math course;
in each section, finite math has 60 students while applied calculus has 50 students
so;
60x + 50y = 6000 --------------lets this be equ 1
we also know that; there are 110 sections in a semester
so;
x + y = 110 ------------------ let this be equ 2
multiply equation 2 by ( - 60 )
-60x + -60y = -6600 --------------- let this be equ 3
now lets add equation 1 and 3
0 - 10y = -600
-10y = -600
divide both sides by (-10)
-10y/-10 = -600/-10
y = 60
now lets substitute value of y in equation 2
x + 60 = 110
x = 110 - 60
x = 50
Therefore, the department should offer 50 sections of finite math and 60 section of applied calculus in order to fill all sections and accommodate all of the students