Question

Ramelteon is a hypnotic agent used in the treatment of insomnia: Considering the labeled drawing above, which of the highlighted atoms has a delocalized lone pair? Select all that apply. 1 2 3 Identify the geometry of each atom (except for hydrogen atoms). All sp2-hybridized carbon atoms have geometry. All sp3-hybridized carbon atoms have geometry. The nitrogen atom has geometry. The oxygen atom of the C=O bond has geometry, and the other oxygen atom has geometry.

Answer 1

Answer:

1 and 2

Trigonal planar

Tetrahedral

Trigonal Planar

Linear

Bent ( v- shape)

Explanation:

The highlighted atoms has a delocalized lone pair - 1 and 2

All sp2-hybridized carbon atoms have geometry- Trigonal planar

All sp3-hybridized carbon atoms have geometry - Tetrahedral

The nitrogen atom has geometry - Trigonal Planar

The oxygen atom of the C=O bond has geometry - Linear

and the other oxygen atom has geometry - Bent ( v- shape)

P.S - The correct question is -

Answer 2

Ramelteon has been an aromatic compound with 3 ring structure followed by the aliphatic chain.

The drug has antagonist structure to the melatonin and has been used to treat insomnia by acting as the melatonin representative.

Geometry in the structure

The labelled atom in the structure is oxygen of the pentane ring, nitrogen in the aliphatic chain, and carbonyl oxygen.

The delocalized lone pair has been observed in the compound which has been contributing to the resonating structure. The delocalized lone pair ion the given structure is oxygen of the pentane ring, and nitrogen in the aliphatic chain.

The geometry of the atom has been based on the hybridization and the lone pairs.

The geometry of $\rm sp^2$ hybridized carbon has been trigonal planar. The geometry of $\rm sp^3$ hybridized carbon atom has been tetrahedral. The nitrogen in the chain has trigonal planar geometry. The C=O oxygen has been comprising  linear geometry, while the oxygen has bent v shape.

Learn more about hybridization, here:

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